# Wrap-Up Exercise

## Overview

Teaching:0 min

Exercises:20 minQuestions

How can we put together all of today’s material?

Objectives

Apply use of functions, conditionals and loops to solve a problem.

## Review From Yesterday

In your notebook, write a function that determines whether a year between 1901 and 2000 is a leap year, where it prints a message like “1904 is a leap year” or “1905 is not a leap year” as output. Use this function to evaluate the years 1928, 1950, 1959, 1972 and 1990.

Essentially, given this list of years:`years = [1928, 1950, 1959, 1972, 1990]`

Produce something like:

`1928 is a leap year 1950 is not a leap year. 1959 is not a leap year. 1972 is a leap year 1990 is not a leap year.`

`8 mod 4 equals 0 10 mod 4 equals 2`

If you’re not sure where to start, see the partial answers below:

## Suggested Approach

First, try to determine how to use the mod operator

`%`

to determine if a year is divisible by 4 (and thus a leap year or not).Then, create a conditional statement to use this information, and put it into a function.

Finally, create a list of the years given in the exercise. Use a for loop and your function to evaluate these years.

## Modular Arthimetic

If a year in the range specified is divisible by four, it is a leap year.

If a number is divisible by 4, then the arithmetic expression “number mod four” (or`num % 4`

in Python) will equal zero.## Conditional Statement

Fill in the blanks:

`year = 1904 if year % 4 == _____: print(year, _______________) ______: print(year, "is not a leap year.")`

## Function

Fill in the blanks:

`def leap_year(year): _________`

## Loop

Fill in the blanks:

`year_list = [1928, 1950, 1959, 1972, 1990] for year in ______: ________(year)`

## Complete Solution

`def leap_year(year): if year % 4 == 0: print(year, "is a leap year") else: print(year, "is not a leap year.") year_list = [1928, 1950, 1959, 1972, 1990] for year in year_list: leap_year(year)`

If you have time:

Expand your function so that it correctly categorizes any year from 0 onwards

Instead of printing whether a year is a leap year or not, save the results to a python dictionary, where there are two keys (“leap” and “not-leap”) and the values are a list of years.

## Key Points

Use skills together.